Respuesta :

Given the following functions

[tex]\begin{gathered} f(x)=x^2-1 \\ g(x)=x-2 \end{gathered}[/tex]

We want to evaluate

[tex](f+g)(t-4)[/tex]

First, let's create this composition of functions. Since it is a sum, we just need to add them together.

[tex](f+g)(x)=f(x)+g(x)=x^2-1+x-2=x^2+x-3[/tex]

Now, to evaluate at t - 4, we just need to substitute our variable for t - 4.

[tex]\begin{gathered} (f+g)(t-4)=(t-4)^2+(t-4)-3 \\ =t^2-8t+16+t-4-3 \\ =t^2-7t+9 \end{gathered}[/tex]

And this is our final answer.

[tex](f+g)(t-4)=t^2-7t+9[/tex]

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