Solve;
[tex]\begin{gathered} g(n)=2n-2 \\ h(n)=n^2+3n \\ \text{Therefore, (g x h) is;} \\ (2n-2)(n^2+3n) \\ =\lbrack2n\times n^2\rbrack+\lbrack2n\times3n\rbrack-\lbrack2\times n^2\rbrack-\lbrack2\times3n\rbrack \\ =2n^3+6n^2-2n^2-6n \\ \text{Collect like terms and you'll have,} \\ =2n^3+4n^2-6n \\ \text{Therefore} \\ (g\mathrm{}h)(n),\text{ now becomes} \\ (2n^3+4n^2-6n)\times n \\ =2n^4+4n^3-6n^2 \end{gathered}[/tex]
