Given the linear equation:
[tex]x-3y=-6[/tex]The single linear equation above contains two variables. Hence, there is no unique solution but infinitely many pairs of solutions. For every value of x, there is a value for y.
Three points that solve the equation would be:
Solution 1
Put x = -6 into the equation
[tex]\begin{gathered} -6-3y=-6 \\ -3y=-6+6 \\ \frac{-3y}{-3}=\frac{0}{-3} \\ y=0 \end{gathered}[/tex]Solution 2
Put x = 0 into the equation
[tex]\begin{gathered} 0-3y=-6 \\ -3y=-6 \\ \frac{-3y}{-3}=\frac{-6}{-3} \\ y=2 \end{gathered}[/tex]Solution 3
Put x = 12 into the equation
[tex]\begin{gathered} 12-3y=-6 \\ -3y=-6-12 \\ -3y=-18 \\ \frac{-3y}{-3}=\frac{-18}{-3} \\ y=6 \end{gathered}[/tex]Therefore, three points that solve the linear equation as shown above are:
[tex]\begin{gathered} (x,y)=(-6,0) \\ (x,y)=(0,2) \\ (x,y)=(12,6) \end{gathered}[/tex]