Can u help me find the centroid of this triangle ?

The coordinates of the centroid are given by:
[tex]\begin{gathered} C=(xc,yc) \\ xc=\frac{Ax+Bx+Cx}{3} \\ yc=\frac{Ay+By+Cy}{3} \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} xc=\frac{4+2+8}{3}=\frac{14}{3} \\ yc=\frac{8+0-4}{3}=\frac{4}{3} \end{gathered}[/tex]The coordinates of the centroid are:
[tex]C=(\frac{14}{3},\frac{4}{3})[/tex]