Question

Triangle JKL is similar to triangle MNO. find the measure of side NO. Round your answer to the nearest tenth if necessary.

Answer 1

Given Data

$\Delta JKL\cong\Delta MNO$

From the propery of the similar triangles,

$\frac{JK}{MN}=\frac{KL}{NO}=\frac{JL}{MO}$

Substituting the know values in the above equation,

$\begin{gathered} \frac{KL}{NO}=\frac{JL}{MO} \\ \Rightarrow\frac{8}{NO}=\frac{11}{49} \\ \Rightarrow NO=\frac{8\times49}{11} \\ \Rightarrow NO=35.63 \end{gathered}$

Thus, the requried value of NO nearest to the tenth is 35.6.