Question

Calculate the force between charges of 5.0 x 10⁻⁸ C and 1.0 x 10⁻⁷ C if they are 5.0 cm apart.

Answer 1

$F=k\frac{q1\cdot q2}{d^2^{}}$

where:

q1= 5.0 x 10⁻⁸ C

q2= 1.0 x 10⁻⁷ C

d = 5 cm = 0.05 m

k = 9 x 10^9 Nm^2/C ( electrical proportionality constant)

Replacing:

F = 9 x 10^9 Nm^2/C *[ ( 5.0 x 10⁻⁸ C * 1.0 x 10⁻⁷ C) / (0.05)^2]

F = 0.018 N