Suppose Jenny borrows $5000 at an interest rate of 16% compounded each year.Assume that no payments are made on the loan.Follow the instructions below. Do not do any rounding.

Suppose Jenny borrows 5000 at an interest rate of 16 compounded each yearAssume that no payments are made on the loanFollow the instructions below Do not do any class=

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Given:

Principal amount = $5000

Interest rate = 16%

Find-:

(a) Amount owed at the end of 1 year.

(b) Amount owed at the end of 1 year.

Sol:

The compound interest rate is:

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Where,

[tex]\begin{gathered} A=\text{ Amount after ''t'' time.} \\ \\ t=\text{ time in year.} \\ \\ r=\text{ Annual interest rate.} \\ \\ n=\text{ The number of times that interest is compounded per year.} \end{gathered}[/tex]

(a)

[tex]\begin{gathered} t=1 \\ \\ n=1 \\ \\ r=\frac{16}{100} \\ \\ =0.16 \\ \\ p=5000 \end{gathered}[/tex]

Amount after one year.

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ =5000(1+\frac{0.16}{1})^{1\times1} \\ \\ =5000(1.16) \\ \\ =5800 \end{gathered}[/tex]

The amount after one year is $5800.

(b)

[tex]\begin{gathered} P=5000 \\ \\ r=0.16 \\ \\ t=2 \\ \\ n=1 \end{gathered}[/tex]

So the amount after two years is:

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ A=5000(1+\frac{0.16}{1})^{1\times2} \\ \\ A=5000(1.16)^2 \\ \\ A=5000\times1.3456 \\ \\ A=6728 \end{gathered}[/tex]

The amount after 2 years is $6728.

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