Question

Report to the standard deck of playing cards if you are unfamiliar with playing cards see the description hereDuring a game of blackjack three players are dealt five cards each and the dealer has five cards. No one has a car that is worth 10 or 11 which would be a 10 a face card or an ace. What is the probability that the next player dealt a car would get a car worth 10 or 11? Express your answer in simplest form.

Answer 1

Answer:

Probability:

$\frac{5}{8}$

Explanation:

Teh formula to calculate probability of and event A of happening is:

$P(A)=\frac{favorable\text{ }outcome}{total\text{ }outcome}$

In this case, the favorable outcome is the amount of cards worth 10 or 11. The cards that worth 10 or 11 are:

4 Jacks

4 Queens

4 Kings

4 10's

4 Aces

This is a total of 4 * 5 = 20

The total outcome are all the cards remaining in the deck. Since 5 cards were dealt to 3 players, and 5 to the dealer, 20 cards were dealt from the deck of 52 cards.

. The total of cards in the deck is:

$52-20=32$

Now we can write:

$P(worth\text{ }10\text{ }or\text{ }11)=\frac{20}{32}$

In simplified form:

$\frac{20}{32}=\frac{5}{8}$