Question

Question 2 Find the 10th term of the sequence -2,-16, -128,-1024... Do not use spaces or commas in your answer.

Answer 1

The first term is -2, and the common ratio is 8.

The nth term of a geometric progression is;

$\begin{gathered} T_n=ar^{(n-1)} \\ T_{10}=2\times(-8)^{10-1} \\ T_{10}=2\times(-8)^9 \\ T_{10}=2\times(-134217728) \\ T_{10}=-268,435,456 \end{gathered}$

The 10th term is equal to -268,435,456