ANSWER
f(x) = -x² - 2x + 15
EXPLANATION
If x1 and x2 are the zeros of a second degree polynomial, the polynomial can be written as,
[tex]P(x)=(x-x_1)(x-x_2)[/tex]In this problem we need to construct a 2nd-degree polynomial function with zeros -5 and 3,
[tex]f(x)=(x+5)(x-3)[/tex]The other property is that f(x) must go to -∞ as x approaches -∞. Therefore, the leading coefficient must be negative, so that the branches of the parabola point downwards,
[tex]f(x)=-(x+5)(x-3)[/tex]Then we can do the multiplication of the factors to obtain the polynomial in standard form,
[tex]f(x)=-(x^2+5x-3x-3\cdot5)[/tex][tex]f(x)=-(x^2+2x-15)[/tex]Distribute the minus sign by changing each coefficient sign,
[tex]f(x)=-x^2-2x+15[/tex]This is a second-degree polynomial function with zeros of -5 and 3 that goes to -∞ as x approaches -∞.
Note: there are other polynomial functions that meet this requirement, this is the simplest one.