Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x + 5BAD=4x+3

Explanation
As BD is a perpendicular bisector
[tex]\begin{gathered} AD=DC\text{ and AC=2AD} \\ \text{replacing} \\ AC=2AD \\ 10x-20=2(40-2x) \\ 10x-20=80-4x \\ 10x+4x=80+20 \\ 14x=100 \\ x=\frac{100}{14} \end{gathered}[/tex][tex]\begin{gathered} \\ \end{gathered}[/tex]