Answer:
[tex]undefined[/tex]
We will firstly pick out 2 ordered pairs that lie along the straight line, we have:
[tex]\begin{gathered} (x_1,y_1)=(-10,-4) \\ (x_2,y_2)=(4,10) \end{gathered}[/tex]
We will proceed to calculate for the slope, we have:
[tex]\begin{gathered} slope,m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ slope,m=\frac{y_2-y_1}{x_2-x_1} \\ \text{Substitute the values for these variables into the formula, we have:} \\ slope,m=\frac{10-(-4)}{4-(-10)} \\ slope,m=\frac{10+4}{4+10} \\ slope,m=\frac{14}{14} \\ slope,m=1 \end{gathered}[/tex]
The equation for the general formula of a straight line becomes:
[tex]\begin{gathered} y=mx+b \\ m=1 \\ y=x+b \end{gathered}[/tex]
We will proceed using the Point-Slope equation to obtain the equation as shown below:
[tex]\begin{gathered} y-y_1=m\mleft(x-x_1\mright) \\ (x_1,y_1)=(-10,-4) \\ m=1 \\ y-\mleft(-4\mright)=(x--10) \\ y+4=(x+10) \\ y+4=x+10 \\ \\ \therefore y+4=x+10(Point-Slope\text{ form}) \end{gathered}[/tex]
