Respuesta :

Given

[tex]\begin{gathered} (1.42+t)\text{ }\times U+\frac{0.42}{V} \\ \\ \text{when t=13.5} \\ U=7 \\ V=6 \end{gathered}[/tex]

Solution

We need replace the letters with the given value

[tex](1.42+13.5)\text{ }\times7+\frac{0.42}{6}[/tex]

Following BODMAS is for order of operation

B for Bracket first

O for Of

D for Division

M for Multiplication

A for Addition

S for Subtraction

Step 1

[tex]\begin{gathered} \text{Let's solve the bracket first} \\ (14.92)\times7+\frac{0.42}{6} \end{gathered}[/tex][tex]\begin{gathered} 14.92\times7+\frac{0.42}{6} \\ \end{gathered}[/tex]

Step 2

Let's solve for multiplication next no Of

[tex]104.44+\frac{0.42}{6}[/tex]

Step 3

Let's solve for division

[tex]104.44+0.07[/tex]

Step 4

Finally we add

[tex]104.44+0.07=104.51[/tex]

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