Respuesta :

SOLUTION

We want to find the missing endpoint T in the line RT, given the point R(-9, 4) and the mid-point S(2, -1)

Since S is the mid-point, we will use the mid-point formula

[tex](x_m,y_m)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

This becomes

[tex]S(2,-1)=(\frac{-9+x_2}{2},\frac{4+y_2}{2})[/tex]

This follows that

[tex]\begin{gathered} \frac{-9+x_2}{2}=2 \\ -9+x_2=4 \\ x_2=4+9 \\ x_2=13 \end{gathered}[/tex]

and

[tex]\begin{gathered} \frac{4+y_2}{2}=-1 \\ 4+y_2=-2 \\ y_2=-2-4 \\ y_2=-6 \end{gathered}[/tex]

Hence the answer is

[tex]T(13,-6)[/tex]

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