The figure above is the combination of a rectangle and a trapezium,
The area of the figure is as follow below,
[tex]\begin{gathered} \text{Area of Shape = Area of Rectangle + Area of Trapezium} \\ =(l\times b)+\frac{1}{2}(a+c)h \end{gathered}[/tex][tex]\begin{gathered} \text{Where l = 23cm and b = 12cm } \\ a=15\operatorname{cm},\text{ l = c = 23cm and h = 6cm} \end{gathered}[/tex][tex]\begin{gathered} \text{Area of shape = (23}\times12)+\frac{1}{2}(15+23)6 \\ =276+\frac{1}{2}(38)6=276+114=390\operatorname{cm}^2 \end{gathered}[/tex]
Hence, the Area of the shape has been deduced above.
