Given
The height of the rollercoaster, h=70.5 m
Initial velocity is zero
To find
The velocity at the bottom
Explanation
Let the velocity be v
By conservation of energy,
Kinetic energy at the bottom is equal to the potential energy at the top
[tex]\begin{gathered} \frac{1}{2}mv^2=mgh \\ \Rightarrow v=\sqrt{2gh} \\ \Rightarrow v=\sqrt{2\times9.8\times70.5}=37.17\text{ m/s} \end{gathered}[/tex]Conclusion
The velocity is 37.17 m/s