Question

The largest possible circle is cut out of a square whose side length is 6

Answer 1

we have that

The area of the remaining board is equal to the area of the square minus the area of the circle

so

$A=b^2-\pi r^2$

where

b=6 ft

r=6/2=3 ft ---------> the radius is half the diameter

pi=3.14

substitute

$\begin{gathered} A=6^2-(3.14)(3)^2 \\ A=7.74\text{ ft}^2 \\ A=8\text{ ft}^2 \end{gathered}$

The area is 8 square feet