SOLUTION
From the question, since the interest is compounded monthly, we will apply the formula
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where A = the amount of money realized after the period = ?
P = the principal, that is the money invested = $1600
r = the interest rate = 3.3%
n = the number of times compounded in a year = 12
t = time interval = 18months = 1.5 years
So, this becomes
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ A=1600(1+\frac{3.3}{100\times12})^{12\times1.5} \\ \\ A=1600(1+0.00275)^{12\times1.5} \\ \\ A=1600(1.00275)^{18} \\ \\ A=1600\times1.05067 \\ \\ A=1681.08\text{ dollars } \end{gathered}[/tex]