Question

Over 32.1 days, a pool's water level changed by an average of -0.21 centimeter each day. What was the total change in the pool's water level?

Answer 1

Multiply the rate of change of water lever with respect to time times the total amount of time to figure out the total change in water level:

$(-0.21\cdot\frac{\operatorname{cm}}{day})\cdot(32.1\text{ days)=-6.741 cm}$

Round the answer up to 2 significant figures:

$-6.741\operatorname{cm}\approx-6.7\operatorname{cm}$

Therefore, the total change in the pool's water level was -6.7 cm.