Respuesta :

From the logarithm quotient rule

[tex]\log (\frac{x}{y})=\log x-\log y[/tex]

we can see that

[tex]\log (\frac{6}{5})=\log 6-\log 5[/tex]

Therefore, expressions a and b are equivalent.

We can corroborate this result because:

[tex]\begin{gathered} \log (\frac{6}{5})=0.07918 \\ \log 6-\log 5=0.7781-0.6989=0.07925 \\ \text{and} \\ \frac{\log 6}{\log 5}=\frac{0.7781}{0.6989}=1.1132 \end{gathered}[/tex]

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