1) The best way to tackle this question is to think of rational equations. Since, time, rate and distance are related.
2) So, we can start writing the following:
[tex]\begin{gathered} t=\frac{d}{r}\Rightarrow rt=d\Rightarrow t=\frac{d}{r} \\ Country\: roads=\frac{3d}{65} \\ Through\: Towns=\frac{d}{35} \end{gathered}[/tex]So, let's solve it by equating the sum of these expressions to the spent time: 4 hours (common to both)
Now we have the LCM
[tex]\begin{gathered} \frac{d}{35}+\frac{3d}{65}=4 \\ \frac{13d+7d}{455}=\frac{1820}{455}\times455 \\ 13d+7d=1820 \\ 20d=1820 \\ \frac{20d}{20}=\frac{1820}{20} \\ d=91 \\ 3d=273 \\ 273+91=364 \end{gathered}[/tex]Note that adding them up, the distance in country roads and the distance in towns.