Given:
• Mass, m = 0.200 mg
,• Speed, v = 3.00 x 10³ m/s
,• Time, t = 6.00 x 10^⁻⁸ s.
Let's calculate the force exerted.
Using the inpulse-momentum theroerm, we have:
impulse = change in momemntum
Where:
Impulse = force x time
change in momentum = mass x velocity.
Thus, we have:
[tex]F\times6.00\times10^{-8}=(0.200\times10^{-6})\times(3.00\times10^3)[/tex]Let's solve for the force F:
[tex]\begin{gathered} F=\frac{(0.200\times10^{-6})(3.00\times10^3)}{6.00\times10^{-8}} \\ \\ F=10000N \end{gathered}[/tex]Therefore, the force exterted is 10000 N.
ANSWER:'
10000 N