Step 1
Given;
Step 2
[tex]\frac{\sqrt{9-x^2}}{\sqrt{3-x}}=\frac{\sqrt{(3-x)(3+x)}}{\sqrt{3-x}}[/tex][tex]\begin{gathered} =\frac{(\sqrt{3-x})(\sqrt{3+x})}{\sqrt{3-x}} \\ =\sqrt{3+x} \end{gathered}[/tex]
Thus, the answer will be; option B
[tex]\sqrt{3+x}[/tex]
