Question

What is the percentage of p2o5 in mg2p2o7?

Answer 1

We need a basis of 100 g mg2p2o7. We need to determine the amount of p2o5 from the amount given. We do as follows:

mass p2O5 = 100 g mg2p2o7 ( 1 mol / 364.4978 g ) ( 1 mol P2O5 / 1 mol Mg2P2O7 ) ( 283.89 g / mol ) = 77.89 g P2O5

Percent = 77.89 / 100 x 100 = 77.89%

Hope this helps. Have a nice day.

Answer 2

The percentage of ${{\text{P}}_{\text{2}}}{{\text{O}}_5}$ in ${\text{M}}{{\text{g}}_{\text{2}}}{{\text{P}}_{\text{2}}}{{\text{O}}_{\text{7}}}$is $\boxed{63.78{\text{\%}}}$.

Further explanation:

Molar mass:

The molar mass of a compound is the summation of masses of all atoms or molecule present in the 1 mole of compound. In other words, Molar mass of a compound is the ratio of mass of compound in grams to the number of moles present of that compound. The S.I unit of molar mass is gram per mol or g/mol.

Step 1: The molar mass of ${\text{M}}{{\text{g}}_{\text{2}}}{{\text{P}}_{\text{2}}}{{\text{O}}_{\text{7}}}$ is calculated as follows:

${\text{Molar mass of}}{\mathbf{}}{\text{M}}{{\text{g}}_{\text{2}}}{{\text{P}}_&{\text{2}}}{{\text{O}}_{\text{7}}}&=\left[\begin{aligned}&{\text{2}}\left({{\text{Atomic mass of Mg}}}\right)+\hfill\\&{\text{2}}\left({{\text{Atomic mass of P}}}\right)+\hfill\\&{\text{7}}\left({{\text{Atomic mass of O}}}\right)\hfill\\\end{aligned}\right]$        …… (1)

The atomic mass of Mg is 24.305 g.

The atomic mass of P is 30.974 g.

The atomic mass of O is 16 g.

Substitute these values in equation (1).

$\begin{aligned}{\text{Molar mass of}}{\mathbf{}}{\text{M}}{{\text{g}}_{\text{2}}}{{\text{P}}_{\text{2}}}{{\text{O}}_{\text{7}}}&=\left[{{\text{2}}\left({{\text{24}}{\text{.305 g}}}\right)+{\text{2}}\left({{\text{30}}{\text{.974 g}}}\right)+{\text{7}}\left({{\text{16 g}}}\right)}\right]\\&=\left[{{\text{48}}{\text{.61 g}}+{\text{61}}{\text{.948 g}}+{\text{112 g}}}\right]\\&=222.558\;{\text{g/mol}}\\\end{aligned}$

Step 2: The molar mass of ${{\text{P}}_{\text{2}}}{{\text{O}}_5}$ is calculated as follows:

${\text{Molar mass of}}{\mathbf{}}{{\text{P}}_{\text{2}}}{{\text{O}}_5}=\left[\begin{aligned}&{\text{2}}\left({{\text{Atomic mass of P}}}\right)+\hfill\\&{\text{5}}\left({{\text{Atomic mass of O}}}\right)\hfill\\\end{aligned}\right]$         …… (2)

The atomic mass of P is 30.974 g.

The atomic mass of O is 16 g.

Substitute these values in equation (2).

$\begin{aligned}{\text{Molar mass of}}{\mathbf{}}{{\text{P}}_{\text{2}}}{{\text{O}}_5}&=\left[{{\text{2}}\left({{\text{30}}{\text{.974 g}}}\right)+{\text{5}}\left({{\text{16 g}}}\right)}\right]\\&=\left[{{\text{61}}{\text{.948 g}}+80{\text{ g}}}\right]\\&=141.948\;{\text{g/mol}}\\\end{aligned}$

The reaction of formation of ${\text{M}}{{\text{g}}_{\text{2}}}{{\text{P}}_{\text{2}}}{{\text{O}}_{\text{7}}}$is as follows:

${\text{2MgO}}+{{\text{P}}_{\text{2}}}{{\text{O}}_5}\to{\text{M}}{{\text{g}}_{\text{2}}}{{\text{P}}_{\text{2}}}{{\text{O}}_{\text{7}}}$

The percentage of ${{\mathbf{P}}_{\mathbf{2}}}{{\mathbf{O}}_{\mathbf{5}}}$in${\mathbf{M}}{{\mathbf{g}}_{\mathbf{2}}}{{\mathbf{P}}_{\mathbf{2}}}{{\mathbf{O}}_{\mathbf{7}}}$can be calculated as follows:

$\begin{aligned}{\text{Percent of }}{{\text{P}}_{\text{2}}}{{\text{O}}_5}\left(\%\right)&=\frac{{{\text{Mass of 1 mole }}{{\text{P}}_{\text{2}}}{{\text{O}}_5}}}{{{\text{Mass of 1 mole M}}{{\text{g}}_2}{{\text{P}}_{\text{2}}}{{\text{O}}_7}}}\times100\\&=\frac{{141.948{\text{ g}}}}{{222.558{\text{ g}}}}\times100\\&=63.78{\text{}}\%\\\end{aligned}$

Learn more:

1. Calculate the moles of ions in the solution: https://brainly.com/question/5950133

2. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: Percentage, p2o5, mg2p2o7, molar mass of a p2o5, molar mass of a mg2p2o7, gram per mol, Mg, O, P, 63.78 %, atomic mass of Mg, atomic mass of P is 30.974 g, atomic mass of O is 16 g.