Write the formula of the function, where xxx is entered in radians.f(x)=

Answer:
[tex]f(x)\text{ = 3cos \lparen}\frac{\pi}{5}x)\text{ + 5}[/tex]Explanation:
Here, we want to write the formula of the function
The general form is:
[tex]f(x)\text{ = Acos\lparen B\lparen x-c\rparen\rparen + D}[/tex]A is the amplitude
D is the mid-value
We have the amplitude as:
[tex]\frac{max-min}{2}\text{ = }\frac{8-2}{2}\text{ = }\frac{6}{2}\text{ =3}[/tex]Now, let us get the period value:
The period is the distance from max to max or from min to min
From the question, we have that as 10
The value of D is the mid-value which is the sum of the y-values divided by 2 (8+2/2 = 5)
Now,let us get the value of B
[tex]B\text{ = }\frac{2\pi}{Period\text{ }}\text{ = }\frac{2\pi}{10}\text{ = }\frac{\pi}{5}[/tex]Thus, we have the equation as:
[tex]f(x)\text{ = 3 cos\lparen}\frac{\pi}{5}x)\text{ + 5}[/tex]