Respuesta :

Answer:

[tex]f(x)\text{ = 3cos \lparen}\frac{\pi}{5}x)\text{ + 5}[/tex]

Explanation:

Here, we want to write the formula of the function

The general form is:

[tex]f(x)\text{ = Acos\lparen B\lparen x-c\rparen\rparen + D}[/tex]

A is the amplitude

D is the mid-value

We have the amplitude as:

[tex]\frac{max-min}{2}\text{ = }\frac{8-2}{2}\text{ = }\frac{6}{2}\text{ =3}[/tex]

Now, let us get the period value:

The period is the distance from max to max or from min to min

From the question, we have that as 10

The value of D is the mid-value which is the sum of the y-values divided by 2 (8+2/2 = 5)

Now,let us get the value of B

[tex]B\text{ = }\frac{2\pi}{Period\text{ }}\text{ = }\frac{2\pi}{10}\text{ = }\frac{\pi}{5}[/tex]

Thus, we have the equation as:

[tex]f(x)\text{ = 3 cos\lparen}\frac{\pi}{5}x)\text{ + 5}[/tex]

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