step 1
solve 2(3x+1) <20
Multiply
6x+2<20
6x<20-2
6x<18
x<3
The solution of the inequality A is the interval (-infinite, 3)
step 2
solve 4(x-1)<2
Multiply
4x-4<2
4x<2+4
4x<6
x<6/4
x<1.5
The solution of the inequality B is the interval
(-infinite, 1.5)
step 3
Find the solution of the compound inequality
the solution is the intersection both solutions
[tex]\begin{gathered} \left(-infinite,3\right)\cap\left(-infinite,1.5\right) \\ \end{gathered}[/tex]the solution is the interval
(-infinite, 1.5)