To answer this question we will use the substitution method.
Solving the second equation for y we get:
[tex]\begin{gathered} 3y-9=15x, \\ 3y=15x+9, \\ y=5x+3. \end{gathered}[/tex]Substituting the above result in the first equation we get:
[tex]10x-2(5x+3)=4.[/tex]Adding like terms we get:
[tex]\begin{gathered} 10x-10x-6=4, \\ -6=4. \end{gathered}[/tex]Now, from the above result, we get that the system is inconsistent, therefore it has no solutions.
Answer: No solution.