Question

Daniel has 2 1/3 hours to work on her homework it takes her one-sixth hour to finish one problem. How many problems can Danielle finish during this time?

Answer 1

We know that

• Daniel has 2 1/3 hours to work.

,

• It takes her one-sixth hour to finish one problem.

First, we have to transform the mixed number into a fraction.

$2\frac{1}{3}=\frac{2\cdot3+1}{3}=\frac{6+1}{3}=\frac{7}{3}$

She has 7/3 hours in total.

Now, if one problem takes her 1/ 6 of an hour, we divide the fractions to know the total number of problems she can finish

$p=\frac{\frac{7}{3}}{\frac{1}{6}}=\frac{7\cdot6}{3\cdot1}=\frac{42}{3}=14$

Therefore, she can finish 14 problems.