Question

consider a diode for which current varies with voltage according to the equation I = V^10.8a. What is the resistance of the diode when a potential difference of 0.58 volts is placed across it?b. What is the resistance of the diode when 0.72 volts is placed across it?

Answer 1

Answer:

a) Resistance of the diode when a potential difference of 0.58 volts is placed across it = 207.1 ohms

b) Resistance of the diode when 0.72 volts is placed across it = 24.8 ohms

Explanation:

The equation representing the relationship between the current and voltage is:

$I=v^{10.8}$

a) When v = 0.58 volts

$\begin{gathered} I=0.58^{10.8} \\ \\ I=0.0028A \end{gathered}$

The resistance of a diode is given as:

$\begin{gathered} R_D=\frac{v_T}{I_D} \\ \\ R_D=\frac{0.58}{0.0028} \\ \\ R_D=207.1\text{ ohms} \end{gathered}$

b) When v = 0.72 volts

$\begin{gathered} I=0.72^{10.8} \\ \\ I=0.029A \end{gathered}$

Calculate the resistance

$\begin{gathered} R_D=\frac{v_D}{I_D} \\ \\ R_D=\frac{0.72}{0.029} \\ \\ R_D=24.8\text{ ohms} \end{gathered}$