Given the poylinomial:
[tex]b^2+4b-12[/tex]We are given the factor b+6 of the factorization, then we need a number that when multiplied with 6, results in -12 and the addition of 6 and this number must be 4, then:
[tex]\begin{gathered} 6+(-2)=4 \\ (6)(-2)=-12 \end{gathered}[/tex]therefore, the missing binomial is b-2