Answer
The probability of drawing a red card or a face card is 8/13
Explanation
Let A be the event of red card, n(A) = 26
Let B represent the event of face card, n(B) = 12
The total possible outcome, n(S) = 52
From mutually exclusive event, (Addition law of probability), we have
p(A∪B) = p(A) + n(B) - p(A∩B)
p(A) = n(A)/n(S) = 26/52
p(B) = n(B)/n(S) = 12/52
But p(A∩B) = 3 + 3 = 6/52 that is (3 clover face cards + 3 spade face cards)
Therefore, the probability of drawing a red card or a face card is
[tex]\begin{gathered} p\mleft(A\cup B\mright)=\frac{26}{52}+\frac{12}{52}-\frac{6}{52} \\ p(A\cup B)=\frac{32}{52} \\ p(A\cup B)=\frac{8}{13} \end{gathered}[/tex]
