Question

What is the equations that models the linear relationship shown in the table?

Answer 1

Solution

For this case we can find the slope with this formula:

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-13+25}{-3+6}=\frac{12}{3}=4$

then the slope is m =4

Now we can find the intercept on this case like this:

We can select the poitn (x= -6, y= -25)

-25= 4(-6)+b

b= -25 +24= -1

Then the correct option is:

y= 4x -1