Respuesta :

To solve the system given

[tex]\begin{gathered} y=-2x-4 \\ y=x+4 \end{gathered}[/tex]

we substitute the value of y from the first equation to the second. This gives

[tex]-2x-4=x+4[/tex]

adding 2x to both sides gives

[tex]-2x-4+2x=x+4+2x[/tex][tex]-4=3x+4[/tex]

subtracting 4 from both sides gives

[tex]-8=3x[/tex]

Finally, dividing both sides by 3 gives

[tex]\boxed{x=-\frac{8}{3}\text{.}}[/tex]

With the value of x in hand, we substitute it into y = x +4 to get

[tex]y=x+4[/tex][tex]y=-\frac{8}{3}+4[/tex][tex]\boxed{y=\frac{4}{3}}[/tex]

Hence, the solution to the system is

[tex](-\frac{8}{3},\frac{4}{3})[/tex]

which is our answer!

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