To solve the system given
[tex]\begin{gathered} y=-2x-4 \\ y=x+4 \end{gathered}[/tex]we substitute the value of y from the first equation to the second. This gives
[tex]-2x-4=x+4[/tex]adding 2x to both sides gives
[tex]-2x-4+2x=x+4+2x[/tex][tex]-4=3x+4[/tex]subtracting 4 from both sides gives
[tex]-8=3x[/tex]Finally, dividing both sides by 3 gives
[tex]\boxed{x=-\frac{8}{3}\text{.}}[/tex]With the value of x in hand, we substitute it into y = x +4 to get
[tex]y=x+4[/tex][tex]y=-\frac{8}{3}+4[/tex][tex]\boxed{y=\frac{4}{3}}[/tex]Hence, the solution to the system is
[tex](-\frac{8}{3},\frac{4}{3})[/tex]which is our answer!