The Solution:
For Mike's Repair charges, the equation:
[tex]\begin{gathered} c=100x \\ \text{ where} \\ c=\text{ cost in dollars} \\ x=\text{ number of hours (time in hours)} \end{gathered}[/tex]
For Sam's Repair charges, the equation is given as:
[tex]\begin{gathered} y=75x+125 \\ \text{ Where} \\ x=\text{time in hours} \\ y=\text{ cost in dollars} \end{gathered}[/tex]
Part (a):
Comparing the total charges for a 2-hour job, we have
[tex]\begin{gathered} \text{ Mike's charges:} \\ \text{when x=2} \\ c=100x=100(2)=\text{ \$200} \end{gathered}[/tex][tex]\begin{gathered} \text{ Sam's charges:} \\ \text{ When x=2} \\ y=75x+125=75(2)+125=150+125=\text{ \$275} \end{gathered}[/tex]
Clearly, we have that:
[tex]\begin{gathered} cThus,
the company that charges less for a 2-hour job is Mike's Repair which charges $200.Therefore, the correct answer is Mike's Repair.
part (b):
To use my understanding of tables, graphs and equations to explain why I chose my answer in part (a):
The fixed charge of $125 by Sam's Repair accounted for his charges,
But Mike's Repair charges $0 as a fixed charge. Hence, the reduced charges especially when the number of hours for the job is less.
[tex]\begin{gathered} 75x+125\leq100x \\ 75x-100x\leq-125 \\ -25x\leq-125 \end{gathered}[/tex][tex]\begin{gathered} x\ge\frac{-125}{-25} \\ \\ x\ge5 \end{gathered}[/tex]
So, the charges for both Repairs can only be equal if the number of hours is 5.