Question

The graph of g(x)=secx has vertical asymptotes whereversinx is undefinedsecx=0secx=∞cosx=0

Answer 1

Answer:

The correct option is D

The function has vertical asymptotes wherever

cos x = 0

Explanation:

Given that

$g(x)=\sec x$

Note that

$\sec x=\frac{1}{\cos x}$

This has vertical asymptotes wherever the denominator is zero, that is;

$\cos x=0$