To determine the equation of the line you have to use the point-slope form
[tex]y-y_1=m(x-x_1)[/tex]Where
(x₁, y₁) are the coordinates of one point on the line
m is the slope
We know two points crossed by the line (0, 4) and (-9,-3), using them we can calulate the slope as:
[tex]m=\frac{y_1-y_2}{x_1-x_2}[/tex]Where
(x₁, y₁) are the coordinates of one point on the line
(x₂, y₂) are the coordinates of a second point on the line
[tex]\begin{gathered} m=\frac{4-(-3)}{0-(-9)} \\ m=\frac{4+3}{9} \\ m=\frac{7}{9} \end{gathered}[/tex]Now that we know the slope of the line, we can determine the equation using
m=7/9 and (0,4)
[tex]\begin{gathered} y-4=\frac{7}{9}(x-0) \\ y-4=\frac{7}{9}x \end{gathered}[/tex]Pass "-4" to the other side of the equation to express the equation in slope-intercept form
[tex]\begin{gathered} y-4+4=\frac{7}{9}+4 \\ y=\frac{7}{9}+4 \end{gathered}[/tex]