Question

Two cows are getting ready to jump over the moon. The height, h, in feet of one cow after t seconds is given by the equation h(t) = -8t^2 + 56t + 160. The height of the other cow is given by the equation h(t) = -8t^2 + 97t. After how many seconds are the cows at the same height?

Answer 1

Given:

The equations for height of cows is,

$h(t)=-8t^2+56t+160$$h(t)=-8t^2+97t$

Explanation:

For the same height the equation are equal. So,

$\begin{gathered} -8t^2+56t+160=-8t^2+97t \\ 97t-56t=160 \\ 41t=160 \\ t=\frac{160}{41} \\ =3.90243 \\ \approx3.902 \end{gathered}$

So after 3.902 seconds two cows are at the same height.