A large stone cube has side length 4 meters and mass 640000 kg. What is the pressure on the ground face of the cube?

Given:
The side length of the cube, a4 m
The mass of the cube, m=640000 kg
To find:
The pressure on the ground face of the cube.
Explanation:
The area of the ground face of the cube is,
[tex]\begin{gathered} A=a^2 \\ =4^2 \\ =16\text{ m}^2 \end{gathered}[/tex]The force applied on the ground face of the cube is equal to the weight of the cube.
The pressure on th ground cface of the cube is given by,
[tex]\begin{gathered} P=\frac{F}{A} \\ =\frac{mg}{A} \end{gathered}[/tex]Where F is the force applied on the ground face of the cube and g is the acceleratin due to gravity.
On substituting the known values in the above equation,
[tex]\begin{gathered} P=\frac{640000\times10}{16} \\ =4\times10^5\text{ Pa} \\ =4\text{E}5\text{ Pa} \end{gathered}[/tex]Final answer:
Thus the correct answer is option f.