Given:
[tex]18x+6y=0\ldots\ldots\ldots(1)[/tex][tex]18x-14y=-60\ldots\ldots\ldots\ldots\ldots(2)[/tex]
To find:
We need find the solution to the given system of equations.
Explanation:
Substract equation (2) from (1).
[tex](18x+6y)-(18x-14y)=0-(-60)[/tex]
[tex]18x+6y-18x+14y=60[/tex]
[tex]18x-18x+6y+14y=60[/tex]
[tex]20y=60[/tex]
Divide both sides of the equation by 20.
[tex]\frac{20y}{20}=\frac{60}{20}[/tex][tex]y=3[/tex]
Substitute y=3 in the equation (1).
[tex]18x+6(3)=0[/tex]
[tex]18x+18=0[/tex]
Subtract 18 from both sides of the equation.
[tex]18x+18-18=0-18[/tex]
[tex]18x=-18[/tex]
Divide both sides by 18.
[tex]\frac{18x}{18}=-\frac{18}{18}[/tex][tex]x=-1[/tex]
Final answer:
The solution is
[tex]x=-1[/tex][tex]y=3[/tex]
