SOLUTION
First, let us use the distance formula to find the distance between (0, 0) and (15, 15), we have
[tex]\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt{(15-0)^2+(15-0)^2} \\ d=\sqrt{15^2+15^2} \\ d=\sqrt{225+225} \\ d=\sqrt{450} \\ d=\sqrt{225\times2} \\ d=15\sqrt{2}\text{ units } \end{gathered}[/tex]The answer is False, because the distance is
[tex]15\sqrt{2}[/tex]