Question

Here is the recursive definition of a sequence (1) = 35, 5(n) = (n-1)-8 for 1 2 2 1. List the first 5 terms of the sequence

Answer 1

We will have that the first 5 terms of the sequence are:

*First: 35.

Second:

$f(2)=(2-1)-8\Rightarrow f(2)=-7$

Third:

$f(3)=(3-1)-8\Rightarrow f(3)=-6$

Fourth:

$f(4)=(4-1)-8\Rightarrow f(4)=-5$

Fifth:

$f(4)=(5-1)-8\Rightarrow f(5)=-4$

***

So, the values are:

35, -7, -6, -5, -4.