Question

Find the 6th term of the geometric sequence whose common ratio is 2/3 and whose first term is 8.

Answer 1

To solve this question, we need to find the formula for the nth term of the geometric sequence. The formula is:

$a_n=a_1r^{n-1}$

Where:

a_n is the nth term of the sequence

a_1 is the first term of the sequence

r is the common ratio

In this case:

a_1 8

r = 2/3

$a_6=8\cdot(\frac{2}{3})^{6-1}=8\cdot(\frac{2}{3})^5=8\cdot\frac{32}{243}=\frac{256}{243}$

The answer is:

256/243