Question

-19x to the 13th power y to the 4th power76x squared y to the 4th power

Answer 1

$Given,\frac{-19x^{13^{}}y^4}{76x^2y^4^{}}$

Step 1 - Separate the integers from the letters

$\frac{-19^{}}{76}\text{ x }\frac{x^{13}}{x^2}\text{ x }\frac{y^4}{y^4}$

Step 2 - Simplify the separated terms/fractions

$\begin{gathered} \frac{-19}{76}\text{ }=\frac{-1}{4} \\ \frac{x^{13}}{x^2}\text{ }=x^{11} \\ \frac{y^4}{y^4}=1^{} \\ \end{gathered}$

Step 3 - Combine all the simplified terms/fractions from step2, and multiply then out the numerators and denominators

$\frac{-1}{4}\text{ x }\frac{x^{11}}{1}\text{ x }\frac{1}{1}=\frac{-x^{11}}{4}\text{ }$

Therefore, the answer to the question is

$\frac{-x^{11}}{4}\text{ or }\frac{-1}{4}x^{11}$