Answer:
The value for x that makes the inequality true is
[tex]x>-16[/tex]Explanation:
Given the inequality:
[tex]-\frac{3}{8}x-2<-13+17[/tex]Add 2 to both sides, we have:
[tex]\begin{gathered} -\frac{3}{8}x-2+2<-13+17+2 \\ \\ -\frac{3}{8}x<6 \end{gathered}[/tex]Multiply both sides by 8
[tex]\begin{gathered} -3x<6\times8 \\ \\ -3x<48 \end{gathered}[/tex]Divide both sides by -3.
Note that this changes the inequality
[tex]\begin{gathered} x>\frac{48}{-3} \\ \\ x>-16 \end{gathered}[/tex]
