Given:
The given function is
[tex]g(x)=21,900(0.91)^x[/tex]
g(x) is the value of a car x years after 2010.
Required:
We need to find the approximate per cent decrease in the value of the car
between 2010 and 2015.
Explanation:
Substitute x=0 in the given equation to find the value of the car in 2010.
[tex]g(0)=21,900(0.91)^0[/tex][tex]g(0)=21,900[/tex]
Substitute x=5 in the given equation to find the value of the car in 2015.
[tex]g(5)=21,900(0.91)^5[/tex][tex]g(5)=13666.3[/tex]
The approximate per cent decrease in the value of the car
between 2010 and 2015.
[tex]\frac{g(0)}{g(5)}\times100=\frac{13666.3}{21900}\times100[/tex][tex]\frac{g(0)}{g(5)}\times100=62\text{ \%}[/tex]
Final answer:
The approximate per cent decrease in the value of the car
between 2010 and 2015 is 62 %.