Solution:
Given the pair of conjugates:
[tex](8j+4)(8j-4)[/tex]To solve the above expression, we multiply the terms in the second parentheses by each term in the first parentheses.
This is done as follows:
[tex]\begin{gathered} (8j+4)(8j-4) \\ \implies8j(8j-4)+4(8j-4) \\ =64j^2-32j+32j-16 \\ but\text{ j}^2=-1 \\ \text{thus, we have} \\ 64(-1)^{}-32j+32j-16 \\ =-64-16 \\ =-80 \end{gathered}[/tex]Hence, we have the product of the conjugate pairs to be -80.
