Answer
Equation: Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)
The PbI₂ is the formed solid precipitate.
Explanation
The balanced equation for the reaction of solutions of lead(II) nitrate and potassium iodide in the test tube is given below:
Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)
The reaction is an example of a double displacement reaction.
The PbI₂ is the formed solid precipitate.
The complete ionic equation for the reaction is:
Pb²⁺(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → 2K⁺(aq) + 2NO₃⁻(aq) + PbI₂(s)
The spectator ions are NO₃⁻ and K⁺
While the net ionic equation for the reaction is:
Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)
