Question

Solve for b.4b - 8 = 2b3b = [?]Hint: Get rid of the fraction first, by multiplyingboth sides by "3".Enter

Answer 1

$\frac{4b-8}{3}=2b$

Multiply both sides by 3:

$\begin{gathered} 3\times(\frac{4b-8}{3})=3\times2b \\ 4b-8=6b \end{gathered}$

subtract 4b from both sides:

$\begin{gathered} 4b-8-4b=6b-4b \\ -8=2b \end{gathered}$

divide both sides by 2:

$\begin{gathered} \frac{2b}{2}=-\frac{8}{2} \\ b=-4 \end{gathered}$