Question

What is the largest of three consecutive integers whose sum is 42. a. X=13 b. X=14C. X=15 d. X=16

Answer 1

Let's represent the three consecutive numbers by 'x', 'x+1' and 'x+2'.

So, if their sum is equal 42, we have:

$\begin{gathered} x+(x+1)+(x+2)=42 \\ 3x+3=42 \\ 3x=39 \\ x=13 \end{gathered}$

Since the largest number is 'x + 2', we have:

$x+2=13+2=15$

So the correct option is C.