ANSWER
[tex]\log (d^rq^x)[/tex]
EXPLANATION
First we apply the rule for the logarithm of a power for each term:
[tex]\log (a^b)=b\log (a)[/tex]
For this problem:
[tex]r\log (d)+x\log (q)=\log (d^r)+\log (q^x)[/tex]
And then, the logarithm of a product rule:
[tex]\log (a\cdot b)=\log (a)+\log (b)[/tex]
In this problem:
[tex]\log (d^r)+\log (q^x)=\log (d^rq^x)[/tex]
